'Finding Product of Array Except Self' cc: hackernoon LeetCode GolitsynSergei java leetcode
Example 1:Follow up:O time and without using the division operation.I will use extra space in this solution, but we can improve the algorithm later and remove additional memory.
We will multiply elements from the left to the right and then from the right to the end exept self element0. nums =[1,2,3,4] 1. leftArr=[1,1,1,1] 2. leftArr=[1,1,1*2,1*2*3] 3. leftArr=[1,1,2,6]0. nums =[1,2,3,4] 1. rightArr=[1,1,1,1] 2. rightArr=[1,1,1*4,1] 3. rightArr=[1,1*3*4,4,1] 3. rightArr=[1*2*3*4,1*3*4,4,1] 4. rightArr=[24,12,4,1]0. leftArr=[1,1,2,6] 1. leftArr=[24,12,4,1] 2. rez =[24, 12, 8, 6]public int[] productExceptSelf { int length=nums.
The concept is simple, you want to calculate the products from both left side and right side . The ans[i] is left * right. I hope it was clear for you guys. Please write comments if something is unclear for you, and I will try to answer.
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